Exponential Functions

[jinx24]

I am having such a tough time with exponential functions.

"Solve the equation"

((x + 4)(10^x))/(x-3) = 2x(10^x)

I first set the whole equation equal to 0 by moving the 2x(10^x) to the other side. Then I factored out the 10^x.

So I have: 10^x((x + 4)/(x - 3) - 2x) = 0
I don't know where to go from here.

Thank you.

 

[pka]

If this is really your problem
\(\displaystyle \L
\frac{{\left( {x + 4} \right)10^x }}{{x - 3}} = \left( {2x} \right)10^x \quad \Rightarrow \quad \frac{{\left( {x + 4} \right)}}{{x - 3}} = \left( {2x} \right)\), just divide by 10<SUP>x</SUP>.

Now it is simple!

 

[Denis]

((x + 4)(10^x))/(x-3) = 2x(10^x)

or do the cross multiplication:

((x + 4)(10^x)) = 2x(10^x) (x-3)

Now easy to see you can cancel out the (10^x)'s