Exponential function help much needed

jklol

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Could someone explain the process of solving these problems


At the beginning of an experiment, a culture contains 200 H. pylori bacteria. An hour later, there are 205 bacteria. Assume that these bacteria grow exponentially according to P(t)=P0e^kt

a) What is the rate of growth, k (percent), of the bacteria? (percent)



b) How many bacteria will there be after 10 hours?



c) How many bacteria will there be after 2 days?





The following table shows the death rate in motor vehicle accidents (per 100,000 population) in selected years.
Year197019801985199019952000
Death Rate26.823.419.318.816.515.6

a) Find an exponential model P(t)=P0e^kt for the data, choosing t = 0 for the year 1970.


b) According to this model, what was the death rate in 2012?




c) According to this model, what is the rate of increase or decrease of the death rate for vehicular accidents?
 
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Could someone explain the process of solving these problems
To learn how to work with exponential growth and decay exercises (which they were supposed to have covered in class and in your book!), try here.

After you have studied at least two lessons from the link, please attempt one of the exercises. If you get stuck, please reply showing your work so far. Thank you! ;)
 
To learn how to work with exponential growth and decay exercises (which they were supposed to have covered in class and in your book!), try here.

After you have studied at least two lessons from the link, please attempt one of the exercises. If you get stuck, please reply showing your work so far. Thank you! ;)
f(1)=205=200(1+r)^t
r=2.5%
f(x)=200(1.025)^x
f(10)
f(2days)=f(48)
?
 
f(1)=205=200(1+r)^t
r=2.5%
f(x)=200(1.025)^x
f(10)
f(2days)=f(48)
?
I will guess that you're working on the first exercise.

At the beginning of an experiment, a culture contains 200 H. pylori bacteria. An hour later, there are 205 bacteria. Assume that these bacteria grow exponentially according to P(t) = P0e^kt
For a start, you might want to try using the formula they told you to use. ;)
 
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