Exponential Function: h(x)=31 x 2.3^x

[cyberspace]

If h(x)= 31 x 2.3^x, find the factor by which to multiply the value of h(x)= h(x+3).

How do I solve this?

I don't know the steps to solve this problem, but I have a feeling I should use the add-multiply property of exponential functions.

Thanks for the help!

 

[stapel]

If h(x)= 31 x 2.3^x, find the factor by which to multiply the value of h(x)= h(x+3).

I'm sorry, but I don't even understand what this question is asking. How would a "factor" of any sort help you solve the equation "h(x) = h(x + 3)"? Why are you supposed to multiply the solution to this equation ("the value") by some number or something?

Were there any further instructions or explanations in the assignment? What related examples are there in your book and/or class notes?

Please be complete. Thank you!

Eliz.

 

[cyberspace]

Sorry! The rest of the instructions were:
Confirm your answer by calculating h(5) and h(8) using the equation, then multiplying h(5) by the factor.

My teacher didn't do any examples related to this problem, and the book doesn't have any either.

But the answer is 12.167.(in the back of my book.)

 

[Deleted member 4993]

Sorry! The rest of the instructions were:
Confirm your answer by calculating h(5) and h(8) using the equation, then multiplying h(5) by the factor.

My teacher didn't do any examples related to this problem, and the book doesn't have any either.

But the answer is 12.167.(in the back of my book.)

\(\displaystyle f(x) = 31 \cdot\ 2.3^x\)

\(\displaystyle f(x+h) = 31 \cdot\ 2.3^{(x+h)}\)

\(\displaystyle f(x+h) = 31 \cdot\ 2.3^{x} \cdot\ 2.3^h = f(x) \cdot\ 2.3^h\)

Now continue....