Exponential Equation

[mathxyz]

How about this one:

PI^(1-x) = e^(x)

I took logs of both sides this way:

1-xlogPI = xloge

Where do I go from there?

 

[Gene]

I'll start on picking on your typing.() () ()
1-xlogPI says multiply log(PI) by -x then add 1 to it.
what you want to say is
(1-x)log(PI) says subtract x from 1 them multiply that by log(PI)
Since there is an e what you REALY want is
(1-x)ln(PI)
log means base 10. ln means base e
Don't you dare tell me you know that. A calculator or tutor must rely on what you show, not what you know.

(1-x)ln(PI) = xln(e) = x
Isolate the x terms on the left.
ln(PI) - x*ln(PI) = x
x*(ln(PI)+1) = ln(PI)
x = ln(PI)/(ln(PI)+1)

 

[mathxyz]

Thanks

I finally get it.