Exponential Distributions: f(t)=e^(-ct), integral from 0 to

[JennW]

I have an improper integral to evaluate on the interval from 0 to infinity. f(t)=e^(-ct) with c being any constant greater than 0. I set it up to take the limit as t is approaching infinity but that is where I am stuck. I don't quite understand how to calculate it so I can move on in the problem.

 

[Dr. Flim-Flam]

Re: Exponential Distributions

F(t) = integral [e^(-ct)],t,0,Inf. = lim b -> Inf of integral [e^(-ct)], t,o,b

= lim b ->Inf [e^(-ct)/-c],0,b = lim b->Inf. [-1/ce^(cb) -(- 1/ce^0)] = 0 +1/c = 1/c