cottoncndy88
New member
- Joined
- Sep 14, 2005
- Messages
- 2
provided information:
half-life of isotope: 1620 yrs
amount after 1000 yrs: 1.5 grams
needed information:
initial quantity:
amount after 10,000 years:
I end up with the equation: 1.5=Ce^(1000)k
I cannot figure out how to solve for both variables with this equation and only this information. Thank you for your efforts.
half-life of isotope: 1620 yrs
amount after 1000 yrs: 1.5 grams
needed information:
initial quantity:
amount after 10,000 years:
I end up with the equation: 1.5=Ce^(1000)k
I cannot figure out how to solve for both variables with this equation and only this information. Thank you for your efforts.