exponent equation

[ugie]

(7^3x)*7=5^x
I can't figure out where to go from here, help please

 

[galactus]

$\displaystyle 7(7^{3x})=5^{x}$

$\displaystyle 7^{3x+1}=5^{x}$

$\displaystyle (3x+1)log(7)=xlog(5)$

$\displaystyle \frac{3x+1}{x}=\frac{log(5)}{log(7)}$

$\displaystyle 3+\frac{1}{x}=\frac{log(5)}{log(7)}$

Now, finish solving for x?.