(7^3x)*7=5^x I can't figure out where to go from here, help please
U ugie New member Joined Apr 5, 2010 Messages 1 Apr 17, 2010 #1 (7^3x)*7=5^x I can't figure out where to go from here, help please
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Apr 17, 2010 #2 \(\displaystyle 7(7^{3x})=5^{x}\) \(\displaystyle 7^{3x+1}=5^{x}\) \(\displaystyle (3x+1)log(7)=xlog(5)\) \(\displaystyle \frac{3x+1}{x}=\frac{log(5)}{log(7)}\) \(\displaystyle 3+\frac{1}{x}=\frac{log(5)}{log(7)}\) Now, finish solving for x?.
\(\displaystyle 7(7^{3x})=5^{x}\) \(\displaystyle 7^{3x+1}=5^{x}\) \(\displaystyle (3x+1)log(7)=xlog(5)\) \(\displaystyle \frac{3x+1}{x}=\frac{log(5)}{log(7)}\) \(\displaystyle 3+\frac{1}{x}=\frac{log(5)}{log(7)}\) Now, finish solving for x?.
