Exploring Angles: Fine value of x if m<ABC=6x, m<1=2x+ and

MathIQ

Junior Member
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Mar 1, 2009
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52
Fine the value of x if m<ABC= 6x, m<1= 2x + and m<2=3x-1
I don't understand how to set it up or how to do it?
Thanks for you help!
 
You need to describe the diagram that goes with this exercise.

Is it a triangle, with vertices labeled A, B, and C?

Which angle is angle 1?

Which angle is angle 2?

Please explain the entire exercise with enough detail for me to understand what it is that you're trying to do.

You also typed the given expression for the measure of angle 1 as: "2x +"

That is supposed to be 2x plus what?
 
YEs it's a triangle and it's verticese are labeled A, B, and C
angle 1 is in BC
angle 2 is in AB

(and the equation with just 2x in i forgot to type 2x plus another number sorry!
So it's

Find the value of x if m<ABC= 6x, m<1=2x+5 and m<2=3x-1

Sorry about that! ;)
 
MathIQ said:
angle 1 is in BC

angle 2 is in AB

Find the value of x if m<ABC= 6x, m<1=2x+5 and m<2=3x-1


I understand that an expression for the measure of angle ABC is 6x.

I do not understand what you mean when you state that angle 1 is in BC.

The expression BC respresents a line segment. It does not make sense to state that an angle is "in" a line segment.

Likewise, it makes no sense to state that angle 2 is "in" the side of the triangle labeled AB.

Please describe the given diagram in detail.

 
So the diagram has linesA, B, C which make angle ABC and there are three lines that make the angle acute and between the 3 lines there is a 2 and then in the another spot there is a 1. I drew something on paint but it wouldn't let me paste it on here, does that help?
 
MathIQ said:
... between the 3 lines there is a 2 and then in the another spot there is a 1 ... does that help?

I regret that this description does not help me.

Phrases like "in another spot there is a 1" are not detailed enough for me to visualize exactly what you're looking at.

This web site does not support direct pasting of images. You need to upload images, first.

Look for two tabs below the text field where you type your posts. These tabs are labeled "Options" and "Upload attachment".

Click on the "Upload attachment" tab.

Now, click the "Browse" button, navigate to the image file that you created using MS Paint, and double-click the filename.

This will copy the path and filename into the field labeled "Filename".

Click the "Add the file" button, and wait for the image file to be uploaded this this web site's server.

When the upload is finished, you'll be returned to your message. Above those two tabs, you should now see two buttons: "Place inline" and "Delete file".

Position the cursor in your message where you would like the image to appear, and click "Place inline".

Click the "Preview" button to see what your post will look like before clicking the "Submit" button. Make any changes you like.
 
[attachment=0:13rabul4]geometry 3.JPG[/attachment:13rabul4][attachment=0:13rabul4]geometry 3.JPG[/attachment:13rabul4]
 

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Thank you for uploading the image.

Angle 1 plus angle 2 equals angle ABC.

Using the given expressions for each of these three angles, we can write an equation.

[2x + 5] + [3x - 1] = 6x

Since the terms 2x, 5, 3x, and -1 can be added in any order (think Commutative Property of Addition), the square brackets are not needed, and we can write these terms in any order.

2x + 3x + 5 - 1 = 6x

Is this enough information for you to find the value of x?

If you need more more, then please show your work and explain what you're thinking, so that I can determine where to continue helping you.



 
Ok so you left me at
2x +3x+5-1=6x
5x+4=6x (this where i started)
I combined like terms is this correct?
And know
5x+4=6x
So I would subtract 5x from both sides with x's
and get 4=x
so 4=x is this correct?
Is there anything else I need to do?
 
Also I have 1 more question involving this picture of the angle i sent you,
It says Find m<2 if m<ABC=75 and m<1=16 so
I was thinking i would take ____ +____ =______
so _75___ + ___16__ =_______ ( then would i add them together to see what they would equal or would i put a measure like 90 degrees, the angle is less then 90 degrees) so would i put 90 degrees?
 
MathIQ said:
... 5x+4=6x (this where i started) If this is the point in your exercise where you got stuck, then why did you wait to me?

In other words, if you started this thread to ask nothing more than how to solve this particular equation, then there is no need for you to upload any images or describe any diagrams.

All that you needed to ask at the very beginning is, "How do I solve the equation 5x + 4 = 6x?"


... so 4=x is this correct?

Yes. The answer to the question "Find the value of x" is: "x equals four".

... Is there anything else I need to do?

Did they ask you any other questions?
 
MathIQ said:
Also I have 1 more question involving this picture of the angle i sent you,
It says Find m<2 if m<ABC=75 and m<1=16 ...


These two measurements are not possible with the given expressions containing x.

If the measure of angle ABC is 75 degrees, then we have the following relationship.

6x = 75

If the measure of angle 1 is 16 degrees, then we have the following relationship.

2x + 5 = 16

The value of x is 25/2 in the first equation, and the value of x is 11/2 in the second equation.

It's not possible for x to have two different values in this exercise, so either you've mistyped information, or you've been given bum information.

Please check your typing.

If we ignore all of the given expressions containing x, then the measure of angle 2 is found by simply subtracting 16 degrees from 75 degrees.

This result will not agree with those expressions containing x, however, so something is wrong somewhere. :?
 
I'm going to type it again but it looked exaclty like what i have typed before

Fine m<2 if m<ABC = 75 and m<1 =16

would i take _75_ + __16__= ___ or does that sound wrong I think that's the way we've been doing other problems like this but idon't think it would be like that it was just my first instinct or would i divide 75 divided by 16?

Sorry i looked it over again and again and again and it was right,[attachment=0:35jqguys]geometry 3.JPG[/attachment:35jqguys]
Also I went on my old one Jeff25 i was seeing if i still remembered my old account and i did but i'm not on that one anymore, but would appreciate it if you could help me on those because no one is helping me :) THanks!
 

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MathIQ said:
would i take _75_ + __16__= ___ or does that sound wrong I think that's the way we've been doing other problems like this but idon't think it would be like that it was just my first instinct or would i divide 75 divided by 16?

Perhaps people are not responding because your English takes too much effort to decipher.

Look at the string of words that you typed above. It ends with a question mark, so I guess you're trying to ask a question. But you typed a string of words that seems to mix a bunch of separate statements together.

This web site is not a chat room. It's not a forum for instant messages, either.

You might get more people to respond, if you write using complete and clear sentences.

I'm going to guess that your instructor used the same diagram for two separate exercises. In other words, I no longer think that the expressions containing x belong with the second exercise.

Angle 1 + Angle 2 = Angle ABC.

16 + ??? = 75



 
I have spoken english all of my life, i'm just typing fast sorry!
 
Yes, this was the first exercise we used.
What I want to do is to take 75-16=59 degrees
But you said that this wouldn't be a complete equation, or that something was missing.
Is there something I'm forgetting?
 
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