"Expand the function" power series questions
- Thread starter rir0302
- Start date
Steven G
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- Dec 30, 2014
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1)What does it mean? The problem is asking you to write \(\displaystyle \dfrac{1}{8+7x}\) in the form given. What are you not understand there?
You know (or should know) that \(\displaystyle \dfrac{1}{1-x}=1 +x+ x^2 + x^3 + x^4 ...\). Do NOT believe what I just said! Do the division yourself and see that my formula is correct. Now basically do the same for \(\displaystyle \dfrac{1}{8+7x}\).
\(\displaystyle \dfrac{1}{8+7x}\) = \(\displaystyle (\dfrac{1}{8})\frac{1}{1+\frac{7}{8}x}\)=\(\displaystyle (\dfrac{1}{8})\frac{1}{1-\frac{-7}{8}x}\).
Continue from here.
You know (or should know) that \(\displaystyle \dfrac{1}{1-x}=1 +x+ x^2 + x^3 + x^4 ...\). Do NOT believe what I just said! Do the division yourself and see that my formula is correct. Now basically do the same for \(\displaystyle \dfrac{1}{8+7x}\).
\(\displaystyle \dfrac{1}{8+7x}\) = \(\displaystyle (\dfrac{1}{8})\frac{1}{1+\frac{7}{8}x}\)=\(\displaystyle (\dfrac{1}{8})\frac{1}{1-\frac{-7}{8}x}\).
Continue from here.