Can you help me, please? Expand and calculate sigma [ n = 0 to n = 5 ] 1/ (n! (n+2) )
S spdrmncoo New member Joined Feb 27, 2006 Messages 20 Dec 12, 2006 #1 Can you help me, please? Expand and calculate sigma [ n = 0 to n = 5 ] 1/ (n! (n+2) )
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Dec 12, 2006 #2 \(\displaystyle \L \sum_{n=0}^5 \frac{1}{n!(n+2)} = \frac{1}{2} + \frac{1}{3} + \frac{1}{8} + \frac{1}{30} + \frac{1}{144} + \frac{1}{840}\)
\(\displaystyle \L \sum_{n=0}^5 \frac{1}{n!(n+2)} = \frac{1}{2} + \frac{1}{3} + \frac{1}{8} + \frac{1}{30} + \frac{1}{144} + \frac{1}{840}\)
