S smsmith New member Joined Sep 15, 2006 Messages 18 Oct 31, 2006 #1 Give the exact value of the six functions of the angle theta whose terminal side passes through the point. (2/3,5/2). I can not figure out how to relate this to the unit circle. I would appreciate any input. Thanks in advance,
Give the exact value of the six functions of the angle theta whose terminal side passes through the point. (2/3,5/2). I can not figure out how to relate this to the unit circle. I would appreciate any input. Thanks in advance,
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Oct 31, 2006 #2 Please review you post. Have you given the correct point? If so, the answers are quite messy.
S smsmith New member Joined Sep 15, 2006 Messages 18 Oct 31, 2006 #3 exact values of six functions That is the correct location. (2/3,5/2) That is probably why I am struggling so mightily with this question. Any input wouls help.
exact values of six functions That is the correct location. (2/3,5/2) That is probably why I am struggling so mightily with this question. Any input wouls help.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Oct 31, 2006 #4 \(\displaystyle \L \begin{array}{l} r = \sqrt {\left( {\frac{2}{3}} \right)^2 + \left( {\frac{5}{2}} \right)^2 } = \frac{{\sqrt {241} }}{6} \\ \cos \left( \theta \right) = \frac{x}{r},\quad \sin \left( \theta \right) = \frac{y}{r}\quad \& \quad \tan \left( \theta \right) = \frac{y}{x} \\ \end{array}.\)
\(\displaystyle \L \begin{array}{l} r = \sqrt {\left( {\frac{2}{3}} \right)^2 + \left( {\frac{5}{2}} \right)^2 } = \frac{{\sqrt {241} }}{6} \\ \cos \left( \theta \right) = \frac{x}{r},\quad \sin \left( \theta \right) = \frac{y}{r}\quad \& \quad \tan \left( \theta \right) = \frac{y}{x} \\ \end{array}.\)
S smsmith New member Joined Sep 15, 2006 Messages 18 Nov 2, 2006 #5 Thanks for the assistance that was very helpful. Now I feel silly for having stuggled with that one. Thanks again!
Thanks for the assistance that was very helpful. Now I feel silly for having stuggled with that one. Thanks again!