how is f(x)= x3+2 an even function. i think it's an odd function but the answer on my packet tells me that it's an even function.
these are my steps...
f(-x)= (-x)3+2= -x3+2. which proves that it's odd because it doesn't match up with the original function. explain why this is an even function!
these are my steps...
f(-x)= (-x)3+2= -x3+2. which proves that it's odd because it doesn't match up with the original function. explain why this is an even function!