evalutating square roots: [(3/4)^2 + (1/2)^3 +....]

[zhyia]

Evaluate: [(¾)² + (½)³ + π]° ÷ (2+X–3X + 3 + 2X -5)

 

[stapel]

I see no "square roots" (from your subject line) in the posted expression and, as was mentioned in one of your similar posts, without values for n or X, it is not possible to evaluate (find the numerical value of) the expression. Sorry.

Eliz.