Evaluate

C

CatchThis2

Junior Member
Joined
Feb 6, 2010
Messages
96
Evaluate the integral.


Need to see step by step how to evaluate one of these problems. Somewhere along the lines I am making mistakes and need to see where I am going wrong.

I know enough to pull the 4 out in front of the integral an the sqrt of x becomes x^1/2.

Next , pull out the 4 and the the sqrt of x becomes x^-1/2 since it is under 4.

Not sure where to go fro there.
 
Need to see your work - we will point out your mistake.....
 
I explained it but don't know how to post it like some of the other fellas on the board. I wish I knew how to draw everything out like them b cause it would make it so much easier.
 


The multiple replies that you've received on these boards to date display (in aggregate) just about all of the standard texting notation for mathematics that you need.

Additionally, there are reference sites available through web searching that provide instruction and examples on how to properly text mathematics.

So, why don't you skip the fancy formatting and simply type your work?

 
Re:

mmm4444bot said:


So, why don't you skip the fancy formatting and simply type your work?
Click to expand...

CatchThis2, if you type/read these two equations (for the time being without Latex),
you may see them being of the form of the third line down typed in Latex:

Integral {4sqrt(x) + 4/[(sqrt(x)}dx =

Integral [4x^(1/2) + 4x^(-1/2)]dx =


\(\displaystyle \int{\bigg(4x^{\frac{1}{2}} + 4x^{\frac{-1}{2}}\bigg)dx\)


\(\displaystyle From \ this \ point \ on, \ are \ you \ able \ to \ provide \ more \ work \ shown \ by \ you \ in \ this \ thread,\)

\(\displaystyle \ by \ applying \ this:\)


\(\displaystyle \ \int{u^n}du \ = \ \frac{u^{n + 1}}{n + 1} \ \ + \ \ \bigg{C} \ ?\)
 
CatchThis2 said:
4x^3/2 +4x^1/2

From there I have to substitute in?
Click to expand...

where did

\(\displaystyle \frac{1}{n+1}\)

part go?

substitute "what" in??
 
Re: Re:

\(\displaystyle \int{\bigg(4x^{\frac{1}{2}} + 4x^{\frac{-1}{2}}\bigg)dx\)

\(\displaystyle = \ 4\cdot \frac{x^{\frac{1}{2}+1}}{{\frac{1}{2}+1}} \ + \ 4\cdot \frac{x^{-\frac{1}{2}+1}}{{-\frac{1}{2}+1}} \ + \ C\)

\(\displaystyle = \ 4\cdot \frac {2}{3}\cdot x^{\frac{3}{2}} \ + \ 4\cdot \frac{2}{1}\cdot x^{\frac{1}{2}} \ + \ C\)

You wore me down.....

You need to practice algebra/arithmatic before trying calculus
 
Thanks for breaking it down for me so I can see the steps. I am following the text book but they go about it in a more complicated fashion. The way you explained it is very clear.
 
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