Evaluate the integral

[OhhCalculus]

I need to evaluate the integral

integral: 6x(x^2+4)^4dx

I know I need to use u-substitution, but I get stuck trying to plug the x in with the 6 attached. Any help would be appreciated.

 

[DrSteve]

$\displaystyle u=x^2+4$

So $\displaystyle du=2xdx$

You can factor $\displaystyle 6$ as $\displaystyle 3\cdot 2$ and take the 3 outside the integral symbol.

 

[OhhCalculus]

Thank you.

I recalculated and ended up with:

3/5(x^2+4)^5 + C

Does that sound about right?

 

[DrSteve]

You got it!