Evaluate the integral

[CatchThis2]

Integral of (x^3+6x^2-14)dx

I got the derivative to be (x^4)/4+(6x^3)/3 -14x

Next I simplified to get (x^4)/4+(2x^3)/3 -14x

Plug in for F(2) and F(1)

I got the final answer to be (15/4)+(56/3)-14

 

[BigGlenntheHeavy]

\(\displaystyle \int(x^{3}+6x^{2}-14)dx \ = \ \frac{x^{4}}{4}+2x^{3}-14x+C\)

 

[swaroop]

You did a small mistake in the second term where 6x^3/3=2x^3 (And not 2x^3/3 as you have done it)