Evaluate the Integral (trig substitution)

goosefraba

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Jan 25, 2011
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I need help with the following problem:

integral of: du/u(sqrt(5-u^2))

Any help with this would be greatly appreciated. I am supposed to use trig substitution to solve it.
 
If you have to use trig sub,let u=5sin(t),   du=5cos(t)dt\displaystyle u=\sqrt{5}sin(t), \;\ du=\sqrt{5}cos(t)dt

15sin(t)5(5sin(t))25cos(t)dt\displaystyle \int\frac{1}{\sqrt{5}sin(t)\sqrt{5-(\sqrt{5}sin(t))^{2}}}\cdot \sqrt{5}cos(t)dt

5cos(t)5sin(t)5(1sin2(t))dt\displaystyle \int\frac{\sqrt{5}cos(t)}{\sqrt{5}sin(t)\sqrt{5(1-sin^{2}(t))}}dt

Now, finish simplifying it down. It whittle down nicely.

Remember, 1sin2(t)=cos2(t)\displaystyle 1-sin^{2}(t)=cos^{2}(t)

If done correctly, you should get it down to 151sin(t)dt=15csc(t)dt\displaystyle \frac{1}{\sqrt{5}}\int\frac{1}{sin(t)}dt=\frac{1}{\sqrt{5}}\int csc(t)dt

Integrating csc is another matter, but it can be looked up or ran through a calculator.
 
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