Evaluate the following limits by factorisation method.

[kartik_new123]

Evaluate the following limits by factorisation method. plz help me my exams are near.

1) lim x -->2 (x/x-2 - 4/x^2-2x)
2) lim x--> 3 (x^2-9) [1/x+3 + 1/x-3]
3) lim x--> 3 (1/x-3 - 2/x^2-4x+3)
I wud Be thankful to the person who can give me a detailed solution.

 

[Deleted member 4993]

1) lim x -->2 (x/x-2 - 4/x^2-2x)
2) lim x--> 3 (x^2-9) [1/x+3 + 1/x-3]
3) lim x--> 3 (1/x-3 - 2/x^2-4x+3)
I wud Be thankful to the person who can give me a detailed solution.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...217#post322217


We can help - we only help after you have shown your work - or ask a specific question (not a statement like "Don't know any of these")

You need to use grouping symbols to clarify your expressions (following "herchy of arithmatic operations" or PEMDAS). For example:

1) as written, lim x -->2 (x/x-2 - 4/x^2-2x) means

\(\displaystyle Lim_{x \to 2}\left (\frac{x}{x} - 2 - \frac{4}{x^2} - 2x \right )\)

but if you meant to write:

\(\displaystyle Lim_{x \to 2}\left (\frac{x}{x - 2} - \frac{4}{x^2 - 2x} \right )\)

you should have written:

lim x -->2 [x/(x-2) - 4/(x^2-2x)]

Those parentheses become very important.


Please share your work with us indicating exactly where you are stuck - so that we may know where to begin to help you.