\(\displaystyle 3^{\frac{1}{2}}\cdot 27^{\frac{1}{2}}\)
For starters, \(\displaystyle x^{\frac{a}{b}}\cdot y^{\frac{a}{b}}=(xy)^{\frac{a}{b}}\)
And secondly, 27 = 3[sup:2ofpvupc]3[/sup:2ofpvupc].
Thirdly, m[sup:2ofpvupc]p[/sup:2ofpvupc]m[sup:2ofpvupc]q[/sup:2ofpvupc]=m[sup:2ofpvupc]p+q[/sup:2ofpvupc].
Finally, (y[sup:2ofpvupc]a[/sup:2ofpvupc])[sup:2ofpvupc]b[/sup:2ofpvupc] = y[sup:2ofpvupc]ab[/sup:2ofpvupc]
