3^1/2 27^1/2
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Sep 9, 2008 #2 312⋅2712\displaystyle 3^{\frac{1}{2}}\cdot 27^{\frac{1}{2}}321⋅2721 For starters, xab⋅yab=(xy)ab\displaystyle x^{\frac{a}{b}}\cdot y^{\frac{a}{b}}=(xy)^{\frac{a}{b}}xba⋅yba=(xy)ba And secondly, 27 = 3[sup:2ofpvupc]3[/sup:2ofpvupc]. Thirdly, m[sup:2ofpvupc]p[/sup:2ofpvupc]m[sup:2ofpvupc]q[/sup:2ofpvupc]=m[sup:2ofpvupc]p+q[/sup:2ofpvupc]. Finally, (y[sup:2ofpvupc]a[/sup:2ofpvupc])[sup:2ofpvupc]b[/sup:2ofpvupc] = y[sup:2ofpvupc]ab[/sup:2ofpvupc]
312⋅2712\displaystyle 3^{\frac{1}{2}}\cdot 27^{\frac{1}{2}}321⋅2721 For starters, xab⋅yab=(xy)ab\displaystyle x^{\frac{a}{b}}\cdot y^{\frac{a}{b}}=(xy)^{\frac{a}{b}}xba⋅yba=(xy)ba And secondly, 27 = 3[sup:2ofpvupc]3[/sup:2ofpvupc]. Thirdly, m[sup:2ofpvupc]p[/sup:2ofpvupc]m[sup:2ofpvupc]q[/sup:2ofpvupc]=m[sup:2ofpvupc]p+q[/sup:2ofpvupc]. Finally, (y[sup:2ofpvupc]a[/sup:2ofpvupc])[sup:2ofpvupc]b[/sup:2ofpvupc] = y[sup:2ofpvupc]ab[/sup:2ofpvupc]
