Evaluate the definite integral...

[flaren5]

I've been trying to work through this problem, I believe that I have figured it out but I'm not completely sure how or if it's even correct. If someone could explain to me how this integration is done, it would be greatly appreciated.



= 43/10

(I don't know how to write the formulas here, so I do the equation in word and then attach it as an image).

 

[mmm4444bot]

You results look good, except for the final answer.

You probably made an arithmetic or substitution error, so please try that last part again.

By the way, you can simplify the antiderivative first:

x^5/10 + 1/x^2 :cool:

 

[flaren5]

You results look good, except for the final answer.

You probably made an arithmetic or substitution error, so please try that last part again.

By the way, you can simplify the antiderivative first:

x^5/10 + 1/x^2 :cool:

I'm assuming when you say that the antiderivative can be simplified first, you are speaking of the x exponents?
Am I to simplify by x²? I'm not too sure how to go about that. I did retry the last part and I got a different answer, which I believe may be correct now.





The answer is 21/5 ? :???:

 

[DrPhil]

I'm assuming when you say that the antiderivative can be simplified first, you are speaking of the x exponents?
Am I to simplify by x²? I'm not too sure how to go about that. I did retry the last part and I got a different answer, which I believe may be correct now.

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The answer is 21/5 ? :???:

Youi have to evaluate the complete antiderivative at x=2, and subtract the value at x=1.

\(\displaystyle \displaystyle \left( \dfrac{2^5}{10} + \dfrac{1}{2^2} \right) - \left( \dfrac{1^5}{10} + \dfrac{1}{1^2} \right) \)

 

[mmm4444bot]

I'm assuming when you say that the antiderivative can be simplified first, you are speaking of the x exponents?

No -- I'm talking about changing your subtraction into a sum.

You wrote the anitderivative as: x^5/10 - (-1/x^2)

That can be simplified to: x^5/10 + 1/x^2