evaluate tan15

TNFC,

the tangent of 15 DEGREES is 0.2679. I just googled 'tangent table' and looked it up. Are you talking about DEGREES??

Bill
 
tnfcsoccer26 said:
evaluate tan15

im just not sure where to start or what to do
Click to expand...

I am assuming you are asked to find the value of tan 15 - without using calculator.

Use

\(\displaystyle \tan (A-B) \, = \, \frac {\tan A - \tan B}{1 \, + \, \tan A \cdot \tan B}\)

and

\(\displaystyle \tan 30^o \, = \frac {1}{\sqrt {3}}\)

\(\displaystyle \tan 45^o \, = 1\)
 
\(\displaystyle \tan\frac{\alpha}{2}=\frac{\sin\alpha}{1+\cos\alpha}\) where alpha = 30°.
 
Why why why do authors continue to introduce circular functions to new students WITHOUT the simple, elegant, UNDERSTANDABLE graphic UNIT CIRCLE. They are so simple and easy, when presented properly.
 
Bill51 said:
Why why why do authors continue to introduce circular functions to new students WITHOUT the simple, elegant, UNDERSTANDABLE graphic UNIT CIRCLE. They are so simple and easy, when presented properly.
Click to expand...

I do not understand your triple question?

Are objecting to "mode" of our response?
 
NO, I am definitely not finding any fault. Its just a pity that the original question needed to be asked. When introduced well, these functions are so easy to understand. I certainly didn't mean to disparage the responses. I am quite in AWE of the effort that the teachers put into this site. I apologize for the ambiguity.
Regards,
Bill
 
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