Evaluate the following indefinate integral ( (1+sqrt[x]) (1-sqrt[x]) ) / (1-x^2)
K kimmy_koo51 Junior Member Joined Sep 19, 2006 Messages 73 Apr 8, 2008 #1 Evaluate the following indefinate integral ( (1+sqrt[x]) (1-sqrt[x]) ) / (1-x^2)
skeeter Elite Member Joined Dec 15, 2005 Messages 3,218 Apr 8, 2008 #2 Re: Evaluate the following integral kimmy_koo51 said: Evaluate the following indefinate integral ( (1+sqrt[x]) (1-sqrt[x]) ) / (1-x^2) Click to expand... a little algebra goes a long way ... (1+x)(1−x)1−x2=1−x1−x2=11+x\displaystyle \frac{(1+\sqrt{x})(1-\sqrt{x})}{1-x^2} = \frac{1-x}{1-x^2} = \frac{1}{1+x}1−x2(1+x)(1−x)=1−x21−x=1+x1 easy to integrate now?
Re: Evaluate the following integral kimmy_koo51 said: Evaluate the following indefinate integral ( (1+sqrt[x]) (1-sqrt[x]) ) / (1-x^2) Click to expand... a little algebra goes a long way ... (1+x)(1−x)1−x2=1−x1−x2=11+x\displaystyle \frac{(1+\sqrt{x})(1-\sqrt{x})}{1-x^2} = \frac{1-x}{1-x^2} = \frac{1}{1+x}1−x2(1+x)(1−x)=1−x21−x=1+x1 easy to integrate now?