These 3 equations all describe the same quadratic function. What are the coordinates of the following points on the graph of the function? From which equation is each point most easily determined?
y = (x - 5) (x + 1)
y = x ^ 2 - 4x - 5
y = (x - 2) ^ 2 - 9
X- intercept, what are the points, the equation, and explanation why that equation is the one from which the x-intercepts are most easily determined?
Is this the correct way to do this problem?
The simple way to graph y = (x - 5) (x + 1) is to generate at least 4 points, put those on graph paper and draw a straight line through them. Here's how I generate the required points: Use the equation y = (x - 5) (x + 1) and choose an integer for x, say x = 2, and substitute this into the equation to find the corresponding value of y.
y = (x - 5) ( x + 1)
y = (2 - 5) ( 2 + 1)
y = (-3) ( 3)
y = -9
So, my first point has coordinates of ( 2, -9). Now I would repeat this operation with a different value of x, say x = 4.
y = (x - 5) (x + 1)
y = (4 - 5) (4 + 1)
y = (-1) (5)
y = -5
So, my second point has coordinates of (4, -5). Now mark these two locations on graph paper. Starting at the origin of my graph (where the x-axis crosses the y-axis), go to the right 2 squares (x = 2) then down 9 squares (y = -9) and mark my first point. For the second point, again, I start at the origin and go right 4 squares (x = 4) and then down 5 squares (y = -5) and mark my second point. Using a straight-edge, draw a line joining these two points. I have now graphed the equation y = (x - 5) (x + 1). Compare the graph with the graph of y = (x - 5) (x + 1).
So far, is this correct? If not, am I thinking of something else? Can someone correct me on how to do this problem?
y = (x - 5) (x + 1)
y = x ^ 2 - 4x - 5
y = (x - 2) ^ 2 - 9
X- intercept, what are the points, the equation, and explanation why that equation is the one from which the x-intercepts are most easily determined?
Is this the correct way to do this problem?
The simple way to graph y = (x - 5) (x + 1) is to generate at least 4 points, put those on graph paper and draw a straight line through them. Here's how I generate the required points: Use the equation y = (x - 5) (x + 1) and choose an integer for x, say x = 2, and substitute this into the equation to find the corresponding value of y.
y = (x - 5) ( x + 1)
y = (2 - 5) ( 2 + 1)
y = (-3) ( 3)
y = -9
So, my first point has coordinates of ( 2, -9). Now I would repeat this operation with a different value of x, say x = 4.
y = (x - 5) (x + 1)
y = (4 - 5) (4 + 1)
y = (-1) (5)
y = -5
So, my second point has coordinates of (4, -5). Now mark these two locations on graph paper. Starting at the origin of my graph (where the x-axis crosses the y-axis), go to the right 2 squares (x = 2) then down 9 squares (y = -9) and mark my first point. For the second point, again, I start at the origin and go right 4 squares (x = 4) and then down 5 squares (y = -5) and mark my second point. Using a straight-edge, draw a line joining these two points. I have now graphed the equation y = (x - 5) (x + 1). Compare the graph with the graph of y = (x - 5) (x + 1).
So far, is this correct? If not, am I thinking of something else? Can someone correct me on how to do this problem?