1038373daj
New member
- Joined
- Sep 8, 2010
- Messages
- 2
Applications:
Question: Height of a projectile: The height of an object thrown upward from the roof of a building 408 ft. tall, with an initial velocity of 96ft/sec. is given by the equation h- -16t^2 + 96t + 408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground? Answer in exact form and decimal form rounded to the nearest hundredth.
Answer: t= 6 + the square root of 138 over 2 sec, t approx = 8.87 sec.
Work so far:
h= -16t^2 + 96 +408
a = -16
b= 96
c= 408
Equation used to solve problem x = - b square root b^2 - 4 (a)(c) over 2(a)
h= -96 square root 96^2 - 4 (-16)(408) over 2(-16)
h= 96 square root of 9216 - 26112 over -32
I'm stuck, im obviously on the wrong path, but i don't know where i went wrong, please help! Also i couldn't find a square root sign so every time it was in the problem i just wrote it out as you can see above, is there an option to put the symbol in to make it easier for you to understand?
Need help asap! Thank You!
Regards, Danielle
Question: Height of a projectile: The height of an object thrown upward from the roof of a building 408 ft. tall, with an initial velocity of 96ft/sec. is given by the equation h- -16t^2 + 96t + 408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground? Answer in exact form and decimal form rounded to the nearest hundredth.
Answer: t= 6 + the square root of 138 over 2 sec, t approx = 8.87 sec.
Work so far:
h= -16t^2 + 96 +408
a = -16
b= 96
c= 408
Equation used to solve problem x = - b square root b^2 - 4 (a)(c) over 2(a)
h= -96 square root 96^2 - 4 (-16)(408) over 2(-16)
h= 96 square root of 9216 - 26112 over -32
I'm stuck, im obviously on the wrong path, but i don't know where i went wrong, please help! Also i couldn't find a square root sign so every time it was in the problem i just wrote it out as you can see above, is there an option to put the symbol in to make it easier for you to understand?
Need help asap! Thank You!
Regards, Danielle