equation



Here's how we type radicals.

x - 6 sqrt(x) = 160

Square both sides.

Form a quadratic equation that looks like ax^2 + bx + c = 0.

Check your candidate solutions! Squaring both sides can introduce false solutions.

Please show your work, if you would like more help.

 
x-6radx=160
x^2 +36x= 25,600
completed the square
x^2+36x+324=25924
(x+18)^2=25924
x=18 +/- rad 25924

That's not the right answer. Where did I go wrong?

Thanks for your help!
 
lwk1219 said:
x-6radx=160
x^2 +36x= 25,600 <<< When you square \(\displaystyle x-6\sqrt{x}\) you get \(\displaystyle x^2 -12\sqrt{x} +36x\)
completed the square
x^2+36x+324=25924
(x+18)^2=25924
x=18 +/- rad 25924

That's not the right answer. Where did I go wrong?

Thanks for your help!
Click to expand...

I would modify the equation to ---> \(\displaystyle 6\sqrt{x} = x - 160\), then square both sides and go from there.
 
lwk1219 said:
ok. I now got down to:
x= 6radX =/-160
how do i solve for x?
Click to expand...
You were told NOT to use "6radX" but to use 6sqrt(x) : you're not listening?

Anyway, Loren told you clearly what to do; but you evidently didn't follow:
you need classroom help; we don't teach here.
 
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