Equation of the tangent line

[Ryan Rigdon]

Find the equation of the tangent line to y = x^2 -4x + 6 at the point (7,27).


my work

Dx(x^2 -4x + 6) = 2x-4

At x = 7

Mtan = 2(7) - 4 = 10


then i used y - y1 = m(x - x1)

y - 27 = 10(x - 7)

y = 10x - 43

So the the equation of the tangent line to y = x^2 -4x + 6 at the point (7,27) is y = 10x - 43


Does my work check out?

 

[galactus]

Yes, it does. You're getting the hang of it.

 

[Ryan Rigdon]

much appreciated galactus