equation of tangent line using chain rule

[amber07213]

Find an equation of the tangent line to the curve
y=sin(sin x)
at the point (pie,0).

ok so I got this far...

y'=cos(sin x)(cos x)

now I'm confused, what's next?

 

[galactus]

If I see one more 'pie' I am going to hire an evil clown to find their house and hit them in the face with one.....some sort of smeary berry pie that leaves stains. :roll: :wink:


You have your derivative. That's the slope. Find the slope at "PI", not PIE.

\(\displaystyle \L\\cos(\pi)cos(sin(\pi))=-1\)

The slope at \(\displaystyle \pi\) is -1.

Now, using y=mx+b, use your given x and y values(pi, 0) and m(-1) to find b.

There you have it. Graph both of them to make sure you're right.

 

[skeeter]

"pie" ...

"pi" ...