Equation of Tangent line to y= x^2-2x+2

d1zz

New member
Joined
Sep 16, 2006
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14
Please help... Im trying to figure this out.

Find the equation of the tangent line to y=x^2-2x+2 at the point (1,1).

THanks for your helps... :p
 
You know that the slope at a point is given by the derivative. Where in the process are you stuck? You've differentiated, you've evaluated at the point to get the slope "m", and... then what?

Please be specific. Thank you.

Eliz.
 
I think I just figured it out! I feel so dumb... Thanks for your help.
 
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