As posted, your function is as follows:sahurn89 said:Find an equation of the tangent line to the curve at the given point:
y= x-1/x-2, (3,2)
So, using the formatting you learned from the articles in the "Read Before Posting" thread, you meant "y = (x - 1)/(x - 2)"...?sahurn89 said:no it is supposed to be written as y= x-1 OVER x-2 with (3,2).
The limit of what? As which approaches zero? What is the relationship, if any, between "a", "h", and "x"? Are you supposed to be using one of the "limit" definitions of the derivative, instead of just taking the derivative?sahurn89 said:what i did was as the lim approaches zero a-1/a-2= 3+h-1/3+h-2 - 2/h