equation of line perp. to 3x = 2y = 12, thru (0, 2)

[art2ista]

find an equation of a line that is perpendicular to 3x=2y=12 and passes through the point (0,2)

i am sorry i wrote it wrong before, i need help please

 

[skeeter]

check your equation again ...

3x=2y=12 ???

did you mean 3x + 2y = 12 ?

change the equation to slope-intercept form ...

3x + 2y = 12
2y = -3x + 12
y = (-3/2)x + 6

the slope of this line is m = -3/2 ... the perpendicular slope is the opposite reciprocal of -3/2, which is 2/3.

you now have the slope of the perpendicular line (2/3), and a point that the perpendicular passes through (0,2)

use the point-slope form of a linear equation to find the equation of the perpendicular line ...

y - y₁ = m(x - x₁)

y - 2 = (2/3)(x - 0)

y - 2 = (2/3)x

y = (2/3)x + 2

 

[stapel]

i need help please

You received complete worked solutions in your other thread for this exercise. Why are you reposting? What, specifcally, is your objection to the answer you have already been provided?

Please reply to this or the original thread, rather than starting another thread on this same exercise. Thank you.

Eliz.

 

[art2ista]

why is it negative at first -3/2 then changes to positve u lost me there

 

[Denis]

start doing a bit of work :
http://www.purplemath.com/modules/slope2.htm

And write legibly: YOU, not u

 

[art2ista]

thanks but i was writing short hand you should be one to talk a werewolf? ok? ok is spelled okay , so you should be one to talk and werewolf?

thanks for the help though

 

[Denis]

Just trying to help you...

2 guys apply for a job; on the application,
one guy writes "you", the other writes "u":
who will get the job?

 

[skeeter]

why is it negative at first -3/2 then changes to positve u lost me there

because two lines that are perpendicular have slopes that are opposite reciprocals.