equation of an line

[Kwesi74]

find the an equation of a line through the point (2,5) with slope 1/2

I tried this problem out and I'm not getting the answer, please help.

 

[tkhunny]

find the an equation of a line through the point (2,5) with slope 1/2

I tried this problem out and I'm not getting the answer, please help.

What did you try? The Point-Slope form will be useful.

y-5 = ½*(x-2)

That's all there is to it. If there was a "trick", it was knowing the form.

 

[Kwesi74]

but I getting a different answer like y=1x+3 but the book have a different answer

 

[Gene]

Show us how you got that from TK's post. And review the distributive rule. I suspect that's where you are going wrong.

 

[Kwesi74]

y-5=1/2x(x-2) book answer choice: y=1/2x+5
y-5=1x-2 y=1/2x+4
+5 +5 y=5x+2
y=1x+3 y=-1/2+4

 

[Gene]

y-5=1/2x(x-2) book answer choice: y=1/2x+5
y-5=1x-2 y=1/2x+4

I was right.
(Do not use x for multiplication. Use *)
y-5=1/2*(x-2) =
(1/2)*x+(1/2)*(-2) =
(1/2)x-1
(It is a good idea to use () to group things, even when it is not strictly necessary. As in
y-5=(1/2)*(x-2)
just to be sure we understand.)

Even though it worked out that Soroban gave a complete solution by a diffeent method we still much prefer that you don't put the same problem on the board twice.