Equation of a graph.

Gobl0010

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I'm taking calc this summer as an independent study. It's a stretch for me. So if I have a graph of a circle that has a radius of 3, the equation forthe circle is x squared + y squared = 9. Just wondering how the equation is obtained, since I can't seem to find the explanation in the book I'm using. If this is not the proper forum, then say so. Thanksdg
 
I'm taking calc this summer as an independent study. It's a stretch for me. So if I have a graph of a circle that has a radius of 3, the equation forthe circle is x squared + y squared = 9. Just wondering how the equation is obtained, since I can't seem to find the explanation in the book I'm using. If this is not the proper forum, then say so. Thanksdg

The standard form of a circle is \(\displaystyle (x-h)^2+(y-k)^2=r^2\) where (h,k) is the center of the circle and r is the radius. The equation you describe would have the center at the origin (0,0), so then you get:

\(\displaystyle (x-0)^2+(y-0)^2=3^2\)

\(\displaystyle x^2+y^2=9\)
 
Just wondering how the equation is obtained

It's been awhile, but I'm thinking that basic geometry and the Pythagorean Theorem were used to derive x^2 + y^2 = r^2. If you pick an arbitrary point on a circle centered at the origin (as long as the point is not on either axis), a right-triangle can be formed by connecting the point to the center and the x-axis.

Did you try googling?
 
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