Equation help

cgarcia71

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Joined
Mar 18, 2006
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It seems as I am really having difficulties understanding how to solve equations. I need help with the following.

I need to solve each system by the substitution method and then determine whether or not the equations are independent, dependent or inconsistent.

x=y+3
3x-2y=4

I am not sure if I am supposed to do anything with the 1st equation because it doesn't seem to be in the right format.

am I supposed to take the second equation and plug do this

3x - 2 (y+3) = 4

Please help me understand... Thanks!
 
cgarcia71 said:
It seems as I am really having difficulties understanding how to solve equations. I need help with the following.

I need to solve each system by the substitution method and then determine whether or not the equations are independent, dependent or inconsistent.

x=y+3
3x-2y=4

I am not sure if I am supposed to do anything with the 1st equation because it doesn't seem to be in the right format.

am I supposed to take the second equation and plug do this

3x - 2 (y+3) = 4

Please help me understand... Thanks!

Hi! You can "plug in" a lamp....but in mathematics, we "substitute" a value or an expression for something that it is equal to.

The first equation,
x = y + 3
tells you that (y + 3) is the same thing as x, and can be used as a replacement for x.

The second equation,
3x - 2y = 4
has an "x" in it. So, in place of that "x", you can substitute something that you know is equal to x, namely (y + 3).

Let's do that substitution:
3x - 2y = 4
3(y+ 3) - 2y = 4

Now, we have an equation with just one variable, y. So, we'll solve it. Start by multiplying each term inside the parentheses by the 3 which is outside:
3y + 3(3) - 2y = 4
3y + 9 - 2y = 4

Next, combine like terms to simplify the expression on the left side of the equals sign. 3y - 2y is 1y, or just y:
y + 9 = 4

Now, we want the variable term to be by itself on the left side. To "undo" the addition of 9, subtract 9 .....but what you do to one side of the equation, you must do to the other side of the equation. So, we'll subtract 9 from sides of the equation:
y + 9 - 9 = 4 - 9
y = -5

So, we have a value for y. We also need a value for x. The first equation tells us that
x = y + 3

We know that y = -5. Substitute -5 for y in
x = y + 3
x = -5 + 3
x = -2

Ok....we have a value for x, and a value for y. So, we have a solution for the system. But, we had better check. Are both equations in the system true when x = -2 and y = -5?

First equation:
x = y + 3
-2 = -5 + 3
-2 = -2 True

Second equation:
3x - 2y = 4
3(-2) - 2(-5) = 4
-6 + 10 = 4
4 = 4 True.

It checks. So, the solution for the system is x = -2 and y = -5.

I hope this helps you.
 
Thank you that helped a lot. I know if takes a while to type all of those instructions out and I want you to know I appreciate you taking the time to do that. My only question now is how do I know if the equations are independent, dependent or inconsistent?

Thanks!

Cindy
 
Cindy - If you follow the procedure given by Mrspi, one of three things will happen:

1) you will get a solution for the two variables -- therefore the equations are independent

2) you will get an identity such as 3 = 3 or 0 = 0 -- then the equations are dependent

3) you will get a false statement like 3 = 4 or 0 = 1 -- then the euqations are inconsistent.

Steve
 
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