Equation for the ellipse

TonyC

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Aug 22, 2005
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How would I go about finding the standard equation for the ellipse, using eithter the giver characteristics, or characteristics taken from the graph.
vertices: (0, +8) ; foci: (0, +2 sq rt15) :?:
 
TonyC said:
How would I go about finding the standard equation for the ellipse, using eithter the giver characteristics, or characteristics taken from the graph.
vertices: (0, +8) ; foci: (0, +2 sq rt15) :?:
First, just write it down.

(x-h)<sup>2</sup>/a<sup>2</sup> + (y-k)<sup>2</sup>/b<sup>2</sup> = 1

Then fill in the parts you can see. The center is exactly between the foci or the vertices. This puts it at the Origin, (0,0), making h = 0 and k = 0, leaving:

x<sup>2</sup>/a<sup>2</sup> + y<sup>2</sup>/b<sup>2</sup> = 1

You should have a relationship between 'a' and 'b' and 'c'. 2*a is the distance between the vertices on the major axis. 2*c is the distance between the foci. 2*b is the distance between the vertices on the minor axis. b<sup>2</sup> = a<sup>2</sup> - c<sup>2</sup>. You have a = 8 and c = 2*sqrt(15).

Where does that leave you?
 
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