Equal court time for 8 person doubles round robin tourney

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Mar 13, 2022
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Looking at 8 person doubles round robin tournaments. I have another criteria: each player play on each court 3 or 4 times. The answers I've seen have 4 players playing on each court 3 or 4 times, but the other players are stuck on one court 5 or 6 times and then play on the other 1 or 2 times. Please help! Thank you.
 
Looking at 8 person doubles round robin tournaments. I have another criteria: each player play on each court 3 or 4 times. The answers I've seen have 4 players playing on each court 3 or 4 times, but the other players are stuck on one court 5 or 6 times and then play on the other 1 or 2 times. Please help! Thank you.
you say:
The answers I've seen have 4 players playing on each court 3 or 4 times, but the other players are stuck on one court 5 or 6 times and then play on the other 1 or 2 times.​

How were these answers calculated? Please share work.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:


Please share your work/thoughts about this problem.
 
One solution:
Court 1 Court 2
1-5 v. 7-8 2-3 v. 4-6
4-7 v. 6-8 1-2 v. 3-5
3-4 v. 5-7 2-6 v. 1-8
1-6 v. 4-5 3-7 v. 2-8
5-6 v. 2-7 1-4 v. 3-8
4-8 v. 2-5 6-7 v. 1-3
1-7 v. 2-4 3-6 v. 5-8

Every person plays each other with player 1 on court 3 times, court 2 4 times. Great!
Player 2 is on court 1 3 times and court 2 4 times. Great!
Player 3 is on court 1 only once and on court 2 6 times! Bad!
Player 4 is on court 1 5 times and court 2 2 times. Bad!
Player 5 is on court 1 5 times and court 2 2 times. Bad!
Player 6 is on court 1 3 times and court 2 4 times. Great!
Player 7 in on court 1 5 times and court 2 2 times. Bad!
Player 8 in on court 1 3 times and court 2 4 times. Great!

I want everyone to have a chance to play each court 3 or 4 times in case one court is subpar for some reason.

Thank you.
 
Last edited:
I want everyone to have a chance to play each court 3 or 4 times in case one court is subpar for some reason.
Unfortunately I don't think this is possible :( However, I have a couple of suggestions.

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This is similar to your solution of post#3, except that:-
- player 1 is on court A 6 times (the number one seed gets the best court)
- players 6,7 & 8 are only on court A twice (the worst ranked players get more time on court B)
- all others play 3 times on court A
Code:
crt A    crt B
==============
12 36    47 58
13 48    26 57
14 27    38 56
15 28    37 46
16 45    23 78
17 35    24 68
25 34    18 67

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Another option:-
- player 1 is always on court A
- all others play 3 times on court A
Code:
crt A    crt B
==============
12 34    56 78
13 57    24 68
14 58    23 67
15 26    37 48
16 38    25 47
17 46    28 35
18 27    36 45
 
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