ellipse has eqns x = 3cos(angle), y = 2sin(angle); find dy/d

[infinitum]

Can anyone help me answer this question:

An ellipse has parametric equations
x= 3cos(angle)
y= 2sin(angle)
(i) find dy/dx at the point with parameter
(ii) find equation of the normal at the general point (3cos(angle),2sin(angle))

Thank you and take care,

 

[Deleted member 4993]

Can anyone help me answer this question:

An ellipse has parametric equations
x= 3cos(angle)
y= 2sin(angle)
(i) find dy/dx at the point with parameter
(ii) find equation of the normal at the general point (3cos(angle),2sin(angle))

Thank you and take care,

Please share with us your work/thoughts - so that we know where to begin to help you.

Hints:

Use chain rule:

\(\displaystyle \frac{dy}{dx} \, = \, \frac{(\frac{dy}{d\theta})}{(\frac{dx}{d\theta})}\)

and

(dy/dx) is the slope of the tangent line at a given point - and normal at a point is perpendicular to the tangent at that point.

 

[tkhunny]

Can anyone help me answer this question:

An ellipse has parametric equations
x= 3cos(angle)
y= 2sin(angle)
(i) find dy/dx at the point with parameter
(ii) find equation of the normal at the general point (3cos(angle),2sin(angle))

Thank you and take care,

Please don't double post. You showed no work in either posting and received almost the exact same reply. This means that you wasted the time and energy of at least on volunteer.

http://www.mathhelpforum.com/math-help/ ... ase-s.html