Eliminating Parameters

[corky0777]

I don't know how to get rid of the parameter in this trig problem. Help please:
eliminate the parameter: x= 3 cos^2(t)+3, y=2 sin^2(t)-1

 

[BigGlenntheHeavy]

$\displaystyle x = 3cos^2(t)+3, \ y \ = \ 2sin^2(t)-1$

$\displaystyle cos^2(t) \ = \ \frac{x-3}{3}, \ sin^2(t) \ = \ \frac{y+1}{2}$

$\displaystyle sin^2(t)+cos^2(t) \ = \ \frac{y+1}{2} \ + \ \frac{x-3}{3}$

$\displaystyle Ergo, \ \frac{y+1}{2} + \ \frac{x-3}{3} \ = \ 1$

 

[corky0777]

wow sweet! Thank you.