Hint: ............... selling price = (original cost) - (amount of loss)Mrs. Barr sold her house for 120,000$. How much did the house cost her if her loss was a) one-third of the cost, b) 20 percent of the cost?
Ans a)$180,000 b)$150,000
Can seem to figure this out..... Need help.
Extremely sorry for the delayed response, but I could not seem to figure out an equation using the variable C, cost.Hint: ............... selling price = (original cost) - (amount of loss)
Please show us what you have tried and exactly where you are stuck.
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Let her original cost be "C". Since she lost money on the sale her selling price must be less than her cost. In fact, by definition of "loss" the selling price must be C minus her loss.
a) Her loss is "one third of the cost", (1/3)C= C/3. Her selling price must be C- C/3= (1- 1/3)C= (2/3)C= 120000. Solve for C by multiplying both sides by 3/2.
b) Her loss is "20 percent of the cost", 0.20C. Her selling price must be C- 0.20C= (1- 0.20)C= 0.80C= 120000. Solve for C by dividing both sides by 0.80.