education assesment exam

Kristigill

New member
Joined
Dec 1, 2011
Messages
1
In printing an article of 48000 words,a printer uses 2 types of type.Using the larger word type,a printed page contains 1800 words.Using a smaller type,the page contains 2400 words.The article is allotted 21 full pages in a magazine.How many pages must be in smaller type?
 
You didn't tell us what you need.

They ask: How many pages must be in small type?

Assign a symbol to represent this unknown number, so that you can write algebraic expressions using the given information.

Let x = the number of pages in small type

Now, we can write stuff like:

the number of pages in large type = 21 - x

Follow that?

Next, we think of a relationship that must be an equality, like:

the total number of large-type words plus the total number of small-type words must equal 48000 words, yes?

The total number of words on each type page is a product: words per page*number of pages .

(In algebra and beyond, we text asterisks to show multiplication because the letter x is already used.)

We know how many words are on each type page because they told us: 2400 and 1800. We have expressions for the number of pages: x and 21-x.

the total number of large-type words = 1800(21 - x)

the total number of small-type words = 2400x

This is enough information to write an algebraic equation to model the relationship above (the one that says all of the words must add up to 48000).

1800(21 - x) + x = 48000

I hope that you were able to follow the set-up.

Can you now determine the value of x, that is, the number of small-type pages?

PS: I forgot to mention that we're assuming something. We're assuming that each page is completely full. In other words, each of the small-type pages contain 2,400 words and each of the large-type pages contain 1,800 words. Without this assumption, there is more than one correct answer. :cool:
 
Last edited:
Top