Easy problem. Need help!

blackandnerdy said:
1/3x+5=-4 The answer is -27 but I don't know how to get it. Please help.

This is a linear equation with one variable - simplest of its kind.

For a quick review - please go to:

http://www.purplemath.com/modules/solvelin.htm

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.
 
Subhotosh Khan said:
blackandnerdy said:
1/3x+5=-4 The answer is -27 but I don't know how to get it. Please help.

This is a linear equation with one variable - simplest of its kind.

For a quick review - please go to:

http://www.purplemath.com/modules/solvelin.htm

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.

This is what I have:

1/3x+5=-4
1/3x+5-5=-4-5
1/3x=-9
1/3x=-27/3
?

This is pretty much what I did.
 
blackandnerdy said:
1/3x+5=-4
--Be more organized please .

Solve for x :
\(\displaystyle \frac{1}{3x} + 5 = -4\)

\(\displaystyle \frac{1}{3x}=-9\)

\(\displaystyle 1=-27x\)

\(\displaystyle x=\frac{-1}{27}\)
 
Aladdin said:
blackandnerdy said:
1/3x+5=-4
--Be more organized please .

Solve for x :
\(\displaystyle \frac{1}{3x} + 5 = -4\)

\(\displaystyle \frac{1}{3x}=-9\)

\(\displaystyle 1=-27x\)

\(\displaystyle x=\frac{-1}{27}\)

x=-27... but i don't know the steps
 
blackandnerdy said:
Aladdin said:
I think you're missing something .

this is the problem: 1/3(x)+5=-4
x=-27

I need to know step by step how to get -27. Thank you for helping!
\(\displaystyle \frac{1}{3}\cdot x \, + \, 5 \, = \, -4\)

\(\displaystyle \frac{1}{3}\cdot x \, = \, -4\, - \, 5 \,\)

\(\displaystyle \frac{x}{3} \, = \, -9\)

multiply both sides by 3

\(\displaystyle \frac{x}{3} \cdot 3 \, = \, -9 \cdot 3\)

\(\displaystyle x \, = \, -27\)
 
blackandnerdy said:
Aladdin said:
I think you're missing something .

this is the problem: 1/3(x)+5=-4
x=-27

I need to know step by step how to get -27. Thank you for helping!

You see the difference to what you've typed at the first time ... The x is for the numerator not for the denomenator
 
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