Greetings,
I'm working on a sheet of earth's characteristics compared to a tennis ball. If I know the weight of the earth in ounces and diameter of the earth in inches, and the diameter of a tennis ball is 2.7", isn't it simple math to obtain a "scale weight" of the tennis ball? Below is how I'm doing this, but I get a huge number of tons which doesn't seem right. Thanks for any opinions!
Earth weight (approx) =
6,479,034,670,000,000,000,000 tons
x 2000 = 12,958,069,340,000,000,000,000,000 pounds
x 16 = 207,329,109,440,000,000,000,000,000 ounces
Earth’s diameter = 7920 miles = 501,811,200 inches
Tennis ball diameter = 2.7 inches
2.7 / 501,811,200 = 0.0000000053805096 size ratio factor
0.0000000053805096 x 207,329,109,440,000,000,000,000,000
= 1,115,536,263,701,370,624 ounces
Divided by 16 = 69,721,016,481,335,664 pounds
Divided by 2000 = 34,860,508,240,668 tons
I'm working on a sheet of earth's characteristics compared to a tennis ball. If I know the weight of the earth in ounces and diameter of the earth in inches, and the diameter of a tennis ball is 2.7", isn't it simple math to obtain a "scale weight" of the tennis ball? Below is how I'm doing this, but I get a huge number of tons which doesn't seem right. Thanks for any opinions!
Earth weight (approx) =
6,479,034,670,000,000,000,000 tons
x 2000 = 12,958,069,340,000,000,000,000,000 pounds
x 16 = 207,329,109,440,000,000,000,000,000 ounces
Earth’s diameter = 7920 miles = 501,811,200 inches
Tennis ball diameter = 2.7 inches
2.7 / 501,811,200 = 0.0000000053805096 size ratio factor
0.0000000053805096 x 207,329,109,440,000,000,000,000,000
= 1,115,536,263,701,370,624 ounces
Divided by 16 = 69,721,016,481,335,664 pounds
Divided by 2000 = 34,860,508,240,668 tons