Just integrate each term-by-term:
For the first integral, let \(\displaystyle \L\ u = -2\sqrt{x}\\), so \(\displaystyle du = -\frac{dx}{\sqrt{x}\\)
So the first integral becomes: \(\displaystyle \L\ \int -e^u\ du\) = \(\displaystyle D - e^u\)
So, \(\displaystyle \L\ D - e^u - y = x + C\), therefore: \(\displaystyle \L\ y = A - e^{-2\sqrt{x}} - x\)
