dy/dx=ycosx/(1+y^2)

[Puk3s]

dy/dx=ycosx/(1+y^2)

This didnt look very hard to me but I ended up with lny + y^2/2 = sinx and I dont know how to solve that for Y

 

[BigGlenntheHeavy]

\(\displaystyle You \ can't \ (solve \ for \ y), \ leave \ it \ as \ is.\)

 

[Deleted member 4993]

Don't forget the constant of integration.