earthboundslave
New member
- Joined
- May 26, 2019
- Messages
- 2
There are three water pipes A, B and C each with water flowing at a constant speed.
If the pipes are used individually to fill up an empty pool, pipe A takes 5 more hours to fill it up than pipe B,
while pipe C takes 2 more hours than pipe B. If the three pipes are used simultaneously,
they take 4 hours to fill up the pool.
Suppose pipe B alone takes x hours to fill up the pool.
(a) Prove that x3 - 5x2 - 46x - 40 = 0
(b) Hence find x by factorizing x3 - 52 - 46x - 40 = 0 .
For part(b), since the function is already there, it is easy.
However, I have absolutely no idea how to draft the function in part(a).
The question only give x as time but no other factors like volume, speed etc. When I tried to draft a function f(x), I don't know what its physical meaning would be in this question. Therefore I have no clue how to use the variable x(time) to draft the function stated in part(a).
If the pipes are used individually to fill up an empty pool, pipe A takes 5 more hours to fill it up than pipe B,
while pipe C takes 2 more hours than pipe B. If the three pipes are used simultaneously,
they take 4 hours to fill up the pool.
Suppose pipe B alone takes x hours to fill up the pool.
(a) Prove that x3 - 5x2 - 46x - 40 = 0
(b) Hence find x by factorizing x3 - 52 - 46x - 40 = 0 .
For part(b), since the function is already there, it is easy.
However, I have absolutely no idea how to draft the function in part(a).
The question only give x as time but no other factors like volume, speed etc. When I tried to draft a function f(x), I don't know what its physical meaning would be in this question. Therefore I have no clue how to use the variable x(time) to draft the function stated in part(a).