I need help with translating double summations relating to discrete math.
$$\sum_{i=1}^{n}
$$\sum_{j=1}^{n} (1) translates to what?
I'm sorry, but I don't understand your formatting above...? Do you mean the following?
. . . . .\(\displaystyle \displaystyle \sum_{i=1}^n\, \sum_{j=1}^n\, 1\)
When you ask "translates to what?", do you mean "evaluates" or "simplified to closed-form"?
the translation goes from 1+1+1...+1
then it equals n^2? how did they even get 1+1...+1 in the first place?
What did
you get when you evaluated the inner summation? You have this:
. . . . .\(\displaystyle \displaystyle \sum_{j=1}^n\, 1\)
So, for j = 1, the term a
j = a
1 = 1. Then, for j = 2, the term a
2 = 1. Then, for j = 3, the term a
3 = 1. And so forth. Then you add all the terms. What then would be the result? And since you're adding n terms (since j counts off from 1 to n), what value will you get?
Then you take this value, and plug it into the outer summation. What is the value of each term? How many of these terms are there? What then is the sum?
Please show all of your work in answering the above questions. Thank you!