Double Integrals

[CatchThis2]

I got 72. What am I doing wrong?

 

[lookagain]

I got 72. \(\displaystyle > \ >\)What am I doing wrong?\(\displaystyle < \<\)

We have no way of knowing, because

\(\displaystyle you \ must \ show \ your \ work \ (attempt) \ first \ so \ we \ can \ see \ what \ your \ approach \ is.\)


\(\displaystyle Edit:\)


The work still must be shown by you, but I worked it out to \(\displaystyle 144\) using the given,
as well as working it in an equivalent form as:


\(\displaystyle \int_0^3\int_0^2(4x^2y^3) \ dy \ dx\)

 

[KEYWEST17]

I got (4y^2 (3)^3/3)-4y^2

Simplified it to 9y^3 from y=2 and y=0

Simplified that to 9(2)^3-9(0)^3

Thats how I got 72 which is incorrect

 

[tkhunny]

It's an integral, not a derivative. Should be y^4.

 

[KEYWEST17]

I corrected it earlier and got 144 which is correct. Sorry for the inconvenience

 

[tkhunny]

What inconvenience? It's what we do, here.