I got 72. What am I doing wrong?
C CatchThis2 Junior Member Joined Feb 6, 2010 Messages 96 Mar 2, 2011 #1 I got 72. What am I doing wrong? Attachments f27e13ffd6fae31483e977205064121.png 1 KB · Views: 48
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,258 Mar 2, 2011 #2 CatchThis2 said: I got 72. > >\displaystyle > \ >> >What am I doing wrong?\(\displaystyle < \<\) Click to expand... We have no way of knowing, because you must show your work (attempt) first so we can see what your approach is.\displaystyle you \ must \ show \ your \ work \ (attempt) \ first \ so \ we \ can \ see \ what \ your \ approach \ is.you must show your work (attempt) first so we can see what your approach is. Edit:\displaystyle Edit:Edit: The work still must be shown by you, but I worked it out to 144\displaystyle 144144 using the given, as well as working it in an equivalent form as: ∫03∫02(4x2y3) dy dx\displaystyle \int_0^3\int_0^2(4x^2y^3) \ dy \ dx∫03∫02(4x2y3) dy dx
CatchThis2 said: I got 72. > >\displaystyle > \ >> >What am I doing wrong?\(\displaystyle < \<\) Click to expand... We have no way of knowing, because you must show your work (attempt) first so we can see what your approach is.\displaystyle you \ must \ show \ your \ work \ (attempt) \ first \ so \ we \ can \ see \ what \ your \ approach \ is.you must show your work (attempt) first so we can see what your approach is. Edit:\displaystyle Edit:Edit: The work still must be shown by you, but I worked it out to 144\displaystyle 144144 using the given, as well as working it in an equivalent form as: ∫03∫02(4x2y3) dy dx\displaystyle \int_0^3\int_0^2(4x^2y^3) \ dy \ dx∫03∫02(4x2y3) dy dx
K KEYWEST17 New member Joined Jan 19, 2011 Messages 46 Mar 2, 2011 #3 I got (4y^2 (3)^3/3)-4y^2 Simplified it to 9y^3 from y=2 and y=0 Simplified that to 9(2)^3-9(0)^3 Thats how I got 72 which is incorrect
I got (4y^2 (3)^3/3)-4y^2 Simplified it to 9y^3 from y=2 and y=0 Simplified that to 9(2)^3-9(0)^3 Thats how I got 72 which is incorrect
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Mar 2, 2011 #4 It's an integral, not a derivative. Should be y^4.
K KEYWEST17 New member Joined Jan 19, 2011 Messages 46 Mar 2, 2011 #5 I corrected it earlier and got 144 which is correct. Sorry for the inconvenience
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Mar 2, 2011 #6 What inconvenience? It's what we do, here.
