Double Integral

[CatchThis2]

Calculate the volume under the elliptic paraboloid

I did (3x^2 y+4y^3/3) from 4 to -4

Next: 3x^2(4)+(4/3)(4)^3-3x^2(-4)+(4/3)(-4)^3 dx

Next: 12x^2+(256/3)- -12x^2 (-256/3)

Next: 24x^3/3+(512/3) from 4 to -4

Next: 8x^3 +(512/3) from 4 to -4

I get 4096/3 which is incorrect

Anyone see where I went wrong?

 

[tkhunny]

If it were me, I would want to know for sure that z stays above the x-y plane. Does it?

12x^2+(256/3)- -12x^2 (-256/3

Very sloppy. Clear this up and emove notational errors. \(\displaystyle 24x^{2} + \frac{512}{3}\)

Next: 24x^3/3+(512/3) from 4 to -4

I suspect your sloppy notation caused this error. It needs to end with "(512/3)x", not just (512/3).

Really, I am not makign this up. Neater and cleaner makes for fewer errors.