Double angel identies - Simplify the expression: 6 - 12sin x cos x

[calc1]

Double angle identies - Simplify the expression: 6 - 12sin x cos x

Simplify the expression: 6-12sin(x)cos(x)

In solving this, I believe I should be getting it into sin2(x) form, but I'm lost.

I think 6-6sin(x), but that is not one of my answer choices.

 

[soroban]

Hello, calc1!

\(\displaystyle \text{Simplify: }\:6 -12\sin x\cos x\)

Factor: .\(\displaystyle 6(1 - \underbrace{2\sin x\cos x})\)
. . . . . . \(\displaystyle =\;6(1 - \overbrace{\sin2x})\)

 

[calc1]

Thanks, soroban.