Actually, it would be \(\displaystyle \L\\sin(\frac{360}{14})\)
You divide 360 by twice the number of sides.
You could also use the law of cosines to find the side length.
Hence, deriving the general formula, knowing the radius (r) and number of sides of your n-gon (n):
\(\displaystyle \L\\r\sqrt{2(1-cos(\frac{360}{n}))}\)
Go ahead and give it a whirl. If you enter in r=14 and n=5, as from your last problem, you get 16.46
If you enter in r=14 and n=7(heptagon), you get 12.15