Dont know where to start: 15.2/sinsin51 = y/sinsin67 = z/sinsin62

russellthedude said:
View attachment 10152

help would be appreciated!
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Do you know whether the "sinsin 51°" is a mistake or is intentional (a sine of a sine)?

Assuming it is meant to be just sin, you can start by solving just the first part:

\(\displaystyle \displaystyle \frac{15.2}{\sin 51°} = \frac{y}{\sin 67°}\).
​

You can use cross-multiplication, or simple algebra. Please show your work, so we can see where, if at all, you need help.
 
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